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s344n2d4d5 [400]
3 years ago
14

Sarah cannot completely remember her four-digit ATM pin number. She does remember the first two digits, and she knows that each

of the last two digits is greater than 5. The ATM will allow her three tries before it blocks further access. If she randomly guesses the last two digits, what is the probability she will get access to her account
Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

3/16 or 0.1875

Step-by-step explanation:

Since she remembers the first two digits, she only has to guess the last two digits. If both digits are greater than 5, there are 4 possible alternatives for each digit (6, 7, 8 or 9).

In three tries, the probability that she will get it right is:

P=\frac{3}{4*4}\\P=\frac{3}{16}=0.1875

The probability she will get access to her account is 3/16 or 0.1875.

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Step-by-step explanation:

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3 years ago
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The multiplication inverse of -3 is?
Murrr4er [49]

-1/3

An example that goes through step by step is below:

The Multiplicative Inverse Property. What number can we multiply to 8 to get 1 (the multiplicative identity) as the answer? So, the multiplicative inverse of 8 is 1/8!

Hope that helps!

6 0
3 years ago
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Please help me with this
GREYUIT [131]

Ths phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be D. the sum of three times a number and six divided by the difference of seven times the number and nine.

<h3>How to illustrate the algebra?</h3>

It should be noted that an algebra is simply used to show the relationship between variables.

Here, the phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be the sum of three times a number and six divided by the difference of seven times the number and nine.

In conclusion, the correct option is D.

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7 0
1 year ago
PLEEEEEEEAAAAAAASSSSSSSSSSEEEEEEEEEEE help me!!!!!!!!!!
defon

Answer:

\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

x^2+5x-84=(x-7)(x+12)

and

x^2+23x-210=(x-7)(x+30)

so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}

hope this helps

7 0
3 years ago
Use a table to compute the product below.
Daniel [21]
(2x+2)(10x^2 - 6x + 8) =
2x(10x^2 - 6x + 8) + 2(10x^2 - 6x + 8) =
20x^3 - 12x^2 + 16x + 20x^2 - 12x + 16 =
20x^3 + 8x^2 + 4x + 16 <==
5 0
3 years ago
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