1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kruka [31]
3 years ago
12

Someone please help

Mathematics
2 answers:
Mademuasel [1]3 years ago
6 0
<h3>Answer:  2y+3 = 4y+2</h3>

========================================================

Explanation:

On the left side, there are two blocks labeled "y". This represents y+y which turns into 2y.

On this same side, we have three blocks labeled "1". So 1+1+1 turns into 3

Overall the expression for the left side is 2y+3

The right side is formed in the same way, just with different values.

On the right we have four "y" blocks leading to 4y. We also have two "1" blocks leading to 1+1 = 2. The expression for the right side is 4y+2

Ultimately we end up with the equation 2y+3 = 4y+2

alexira [117]3 years ago
5 0

i would be so scared

You might be interested in
Which of the following inequalities matches the graph?
S_A_V [24]
X<-3 would be the answer
7 0
3 years ago
Which value of x makes the equation true? ​
boyakko [2]

Answer:

B

Step-by-step explanation:

If you plug in -9 you will get -11 for both side.

8 0
3 years ago
Read 2 more answers
A robot has a straight arm 20 inches long that can rotate about the origin of a coordinate system. If the robot’s hand is locate
scoundrel [369]

Answer:

The location of the robots hand after rotating 45° counterclockwise from (-20, 0) in inches is (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0)) in inches is (-14.14, -14.14)

Step-by-step explanation:

The initial location of the robots hand = (-20, 0)

The angle through which the robot rotates his hand = 45°

∴ We have the length of the robots hand = 20 inches

We note that (-20, 0) is in the 2nd Quadrant

The location of the robots hand after rotating 45° counterclockwise = 135°

Therefore, the location of the robots hand after the rotation = (20×cos(135°), 20×sin(135°)) = (-10·√2, 10·√2) = (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0) = 225°

Therefore, the location of the robots hand after the rotation = (20×cos(225°), 20×sin(225°)) = (-10·√2, -10·√2) = (-14.14, -14.14)

8 0
3 years ago
I need help with shapes, can someone help me with this problem
posledela

Answer:

90%

Step-by-step explanation:

9/10's of the two rectangles are shaded and 9/10 = 90%

7 0
3 years ago
Read 2 more answers
Is a triangle with two 45 degree angles unique
notka56 [123]

Answer:

No. It's just a 90° angle.

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • paul has a paperweight shaped like a square pyramid shown what is the total area in square centermeters
    5·2 answers
  • The perimeter of a rectangle is 42 feet. The length decreased by three times the width is 1 foot. What are the dimensions of the
    10·1 answer
  • Given 11 is conguent to 3, which lines, if any, must be parallel based on the given information? Justify your conclusion
    15·1 answer
  • Solve the radical equation.
    14·1 answer
  • What is the value of z for the parallelogram shown? <br><br> A.130 <br> B.40<br> C.10<br> D.26
    13·2 answers
  • ∆ABC is similar to ∆DEF. The ratio of the perimeter of ∆ABC to the perimeter of ∆DEF is 1 : 10. The longest side of ∆DEF measure
    10·1 answer
  • The slope of the line below is -4. use coordinates of the labeled point to find a point-slope equation of the line.
    12·1 answer
  • The selling price of an item is ​$480. It is marked down by ​10%, but this sale price is still marked up from the cost of ​$. Fi
    12·2 answers
  • Will give Brain!! To this
    6·2 answers
  • Flying against the wind, a jet travels 2190 miles in 3 hours. Flying with the wind, the same jet travels 9520 miles in 8 hours.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!