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ira [324]
2 years ago
13

Can someone put an example of how to do bearings for precal?

Mathematics
1 answer:
Reika [66]2 years ago
4 0

Answer:

A bearing is used to represent the direction of one point relative to another point. For                                                                                                                          example, the bearing of A from B is 065º. The bearing of B from A is 245º.

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lan has a flower pot in the shape of a rectangular prism . The base of the flower pot is 36 square inches . The flower he's plan
JulijaS [17]

Answer:

108

Step-by-step explanation:

  1. volume = area  of the base * height
  2. Area of the base = 36 square inches .
  3. The height = 3 inches
  4. 36 * 3 = 108
4 0
3 years ago
Please this is a test
amid [387]
5

you use the formula a^2+b^2=c^2

a=3, b=4

3*3=9 and 4*4=16

16+9=25

square root of 25 is 5.


5 is the answer
7 0
2 years ago
Read 2 more answers
✨6 Grade Math✨ PLEASE HELP I RLLY DONT GET IT
ratelena [41]

Answer:

a. 12s + 19j - 3

36 + 28 - 3 = 61

b.

Shirt (per unit cost):

Before Discount: $12

After Discount: $12 - $3 = $9

Jeans (pair cost):

Before Discount: $19

After Discount: $19 - $3 = $16

(12-3)s + (19-3)j

27 + 32 =  $59

8 0
3 years ago
Which represents a function?
ollegr [7]

Answer:

Only the given table represents a function. Option 1 is correct.

Step-by-step explanation:

A relation is called a function, if there exist a unique value of y for each value of x. It means for each input there exist a unique output.

A function is always a relation but all relations are not function.

In the given table for each value of x, we have unique value of y, therefore the given table represents a function.

In second relation, at x=-2, the values of y are y=10 and y=-7. For single x, there are more than one value of y, therefore the second relation is not a function.

In third relation, at x=6,  the values of y are y=-2 and y=1. For single x, there are more than one value of y, therefore the third relation is not a function.

5 0
3 years ago
Read 2 more answers
Sharon was going through the financial records of her company. The profit earned by the company, p(t), over time t, in years, fo
FromTheMoon [43]
For this case what we must do is find a quadratic function that is already factored.
 This is because in the factored quadratic equations, it is easier to observe the zeros of the function.
 In this case, the zeros of the function represent the time at which the company did not make any profit.
 We have the following equation:
 p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
 We observed that there was no gain in:
 t = 3
 t = 5
 The other roots are discarded because they are negative
 Answer:
 
a.p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
5 0
3 years ago
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