What are the coordinates of the image of ΔABC after a dilation with center (0, 0) and a scale factor of 3? Drag numbers to compl
ete the coordinates. Numbers may be used once, more than once, or not at all.
2 answers:
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Answer:
b) The width of the confidence interval becomes narrower when the sample mean increases.
Step-by-step explanation:
The confidence interval can be calculated as:
a) The width of the confidence interval becomes wider as the confidence level increases.
The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.
b) The width of the confidence interval becomes narrower when the sample mean increases.
The above statement is false. As the sample mean increases the width of the confidence interval increases.
c) The width of the confidence interval becomes narrower when the sample size n increases.
The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.
Answer:
, 
Explanation:
2√2 sin(q) + 2 = 0
2√2 sin(q) = -2
sin(q) =
sin(q) =
Now, we know that:
sin (45) =
From the ASTC rule, we know that the sine function is negative in the third and fourth quadrant.
This means that:
either q = 90 + 45 = 135° which is equivalent to
or q = 270 + 45 = 315° which is equivalent to
Hope this helps :)
Explanation:
2√2 sin(q) + 2 = 0
2√2 sin(q) = -2
sin(q) =
sin(q) =
Now, we know that:
sin (45) =
From the ASTC rule, we know that the sine function is negative in the third and fourth quadrant.
This means that:
either q = 90 + 45 = 135° which is equivalent to
or q = 270 + 45 = 315° which is equivalent to
Hope this helps :)