The formula for volume of cone is:
V = π
r^2 h / 3
or
π r^2
h / 3 = 36 cm^3
Simplfying in terms of r:
r^2 = 108 / π h
To find for the smallest amount of paper that can create
this cone, we call for the formula for the surface area of cone:
S = π
r sqrt (h^2 + r^2)
S = π
sqrt(108 / π h) * sqrt(h^2 + 108 / π h)
S = π sqrt(108 / π h) * sqrt[(π h^3 + 108) / π h]
Surface area = sqrt (108) * sqrt[(π h + 108
/ h^2)]
<span>Getting the 1st derivative dS / dh then
equating to 0 to get the maxima value:</span>
dS/dh = sqrt (108) ((π – 216
/ h^3) * [(π h + 108/h^2)^-1/2]
Let dS/dh = 0 so,
π – 216
/ h^3 = 0
h^3 = 216 / π
h = 4.10
cm
Calculating
for r:
r^2 = 108 / π (4.10)
r = 2.90 cm
Answers:
h = 4.10 cm
<span>r = 2.90 cm</span>
Answer:
Where is the statement mate
A=31/8 and B=13/5 all you would do is times the whole number by the denominator and than add that answer and the numerator
-2(3z+8)=1/3(9-18z)
-6z-16=1/3(9-18z)
-6z-16=1/3(-18z+9)
-6z-16=1(-18z+9)
———-
3
0=57
The input has no solution
Answer:
The distance of needle cover as it rotate is 0.700688 cm
Step-by-step explanation:
Given as :
The length of the needle = r = 24 cm
The needle is rotated at angle = Ф = 96°
The distance of needle cover as it rotate = length of arc made = l cm
The radius of arc = length of needle = r cm
<u>Now, According to question</u>
The distance of needle cover as it rotate = 
where , π = 3.14
Or, l = 
Or, I = 
Or, l = 75.36 × 0.533°
∵ 180° = 3.14 radian
So, 0.533° = 0.0092978
So, l = 75.36 × 0.0092978
∴ l = 0.700688 cm
So,The distance of needle cover as it rotate = l = 0.700688 cm
Hence, The distance of needle cover as it rotate is 0.700688 cm Answer
