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olganol [36]
3 years ago
9

Find the volume of a pyramid with a square base, where the perimeter of the base is 13.4 in and the height of the pyramid is 7.6

in. Round your answer to the nearest tenth of a cubic inch.
Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:

28.4in³

Step-by-step explanation:

Volume of the square based pyramid = L²H/3 where;

L is the length of a side of the square base

H is the height of the prism

Given

Perimeter of the base = 13.4 in

Height of the pyramid = 7.6in

First we need to get the length of the square base

Perimeter of a square = 4L

13.4 = 4L

L = 13.4/4

L = 3.35 in

Next is to find the required volume of the pyramid

V = L²H/3

V =  3.35²(7.6)/3

V = 85.291/3

V =  28.4 in³

Hence the volume of the pyramid to nearest tenth is 28.4in³

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Answer:

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Step-by-step explanation:

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Substitute the values then we get

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Again differentiate w.r.t x

V''(x)=24x-92

Substitute x=6

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Substitute x=5/3

V''(5/3)=24(5/3)-92=-52

Hence, the volume is maximum at x=\frac{5}{3}

Therefore, the side of the square ,x=\frac{5}{3} in cutout that gives the box the largest possible volume.

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