Answer:
0.25
Step-by-step explanation:
We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.
On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by
(3C1)(5C2)=(3)(10)=30 and
Pr(A∩B)=30/120=0.25
Answer:
D) $8.20
Step-by-step explanation:
82 x 0.1 = 8.2
Answer:
87.92
Step-by-step explanation:
3.14(a²+ab)=
<em>Plugging in values for a and b</em>
3.14(4²+4×3)=
3.14(16+12)=
3.14(28)=
87.92
Your answer is c
Hope this helps :)
Where you are. The moon or the earth is the independent variable
