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Inga [223]
2 years ago
6

What transformations have been done to y = - 4(x + 3)^2 - 5 as compared to y = x^2​

Mathematics
1 answer:
ohaa [14]2 years ago
4 0

Answer:

y=x^2 is the parent function

The transformations for y=-4(x+3)^2-5 are as follows

horizontal shift left 3 units

vertical shift down 5 units

reflection across the x-axis

vertical stretch

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Answer:

Answer C is correct

Step-by-step explanation:

-200(3/4) = -600/4 = -150 ft

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Rebecca needs 10 1/2 yards of fabric to make quilt. She has one piece of fabric that is 2 1/2 yards and another piece of fabric
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-15/4

Step-by-step explanation:

Add 2 1/2 and 4 1/4

Take that fraction and subtract it from 10 1/2

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There is a 1/6 probability
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I can’t seem to find the value of n in this peoblem
Annette [7]

Answer:

9

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124 seems rather high

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3 years ago
Read 2 more answers
A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic
Ket [755]

Answer:

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

Step-by-step explanation:

Data given and notation  

\bar X=5.25 represent the sample mean

s=3.98 represent the sample standard deviation

n=54 sample size  

\mu_o =4.73 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:  

Null hypothesis:\mu =4.73  

Alternative hypothesis:\mu \neq 4.73  

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

7 0
3 years ago
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