What does not show for u?
Answer:
Step-by-step explanation:
Given that g is a function from A to B and f is a function from B to C.
g: A -->B and f: B-->C
a) fog= f{g[x)} is a function from A to C
Let fog be onto. Then we get for any element C in f we got an image in A.
This is possible only if every element of C has an image in B because if not then f cannot be applied to g(x).
Hence proved
b) Let fog be one to one.
i.e. fog(a) = fog(b) implies a =b
This suggests that f{g(a) }=f{g(b)}
Since f is a function for g(a) and g(b) three exists unique images.
So g(a) = g(b) implies a = b.
g is one to one
c) If fog is one to one and on to then we have f is onto and g is one to one.
Since f is onto every element in g has a preimage so it follows that both f and g are bijective.
Answer:2.23607
Step-by-step explanation:
\sqrt{5} (cos(0) + i × sin (0))
\sqrt{5} (cos(π) + i × sin (π))
Hi there!
To solve your answer, since we know a = 7, we can easily solve your equation.
But before we go onto that, I want to show you a tip or two about solving equations with variables next to numbers.
When you have a number, and a variable attached to it, it means to multiply.
Now, to make this equation look a little easier, lets rewrite it.
9 × 7 - 5 × 7 = ___
According to PEMDAS, we won't go straight from left-to-right when solving here. We'll skip around a little.
9 × 7 = 63.
5 × 7 = 35.
Now, since we've multiplied the two numbers, its time to subtract them.
63 - 35 = 28. Sooooo........
9 × 7 - 5 × 7 = 28
Hope this helps!
Message me if you need anything else, I'd be happy to help you out! :D
Answer:
18
Step-by-step explanation: