PLEASE HELP ASAP!!!!

Mathematics

1 answer:

DaniilM [7]2 years ago

7 0

Answer:

An independent clause is a group of words that contains both a subject and a predicate. It expresses a complete thought and can stand alone as a sentence. It can also be joined to other dependent or independent clauses to make a more interesting and complex sentence.Step-by-step explanation:

You might be interested in

A local hardware store sold 12 percent of its hammers on Saturday . If the hardware store sold 9 hammers on Saturday how many ha

Dmitrij [34]

$\frac{12}{100}$ = $\frac{9}{x}$ Cross multiply

12x=900 Divide both sides by 12.

x=75 hammers to begin with.

7 0

3 years ago

A school has 1,000 students on Wednesday, 300 students went on a field trip. What percent of students did not go on the field tr

iris [78.8K]

Answer:

%70

Step-by-step explanation:1,000=%100 300+%30 1000 - 300 = 700 so 700 + %70

7 0

2 years ago

PLEASE HELP ME FIND THE CORDINATES FOR THESE GRAPHSSS PLEASE ILL GIVE YOU BRAINLIEST AND 25 POINTS

tia_tia [17]

1. (-1,-1) (2,-2)
2. (-3,0) (2,0)
3. (-4,-3) (-1,2)

7 0

2 years ago

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$