Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
Add. I’m not sure because there is a - besides the 15.
Explanation - 12 + 15 = 27.
Hopefully this helps. Have a blessed one. God loves you. ☺️
Answer:
Step-by-step explanation:
First, we need to isolate 
by taking it common from both terms on the right:
Now, since we want in terms of the other variables, we can divide the left hand side (A) by whatever is multiplied with on the right hand side. Then we will have an expression for . Shown below:
This is the xpression for
Answer:
$2561.50
Step-by-step explanation:
If the account earns simple interest, then the balance at the end of 6 months will be ...
... A = P + Prt . . . . . for principal amount P, interest rate r, time period t
... A = $2350 +2350·0.18·6/12 = $2350 + 211.50
... A = $2561.50
