Please Help w/ These Math Problems, Thanks!
1 answer:
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*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*
(21)
Area of a Regular Hexagon: square units
(22)
Similar to (21)
Area = square units
(23)
For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:
Hence, area of the hexagon will be: square units
(24)
Given is the inradius of an equilateral triangle.
Substituting the value of inradius and calculating the length of the side of the equilateral triangle:
Side = 16 units
Area of equilateral triangle = square units
Usando el concepto de pendiente, se encuentra que el cambio en la distancia horizontal es de 10 pies.
La pendiente de una reta es la <u>razón entre el cambio vertical y el cambio horizontal,</u> o sea, cual el cambio vertical cuando el cambio horizontal es de 1.
En este problema, hay que:
- La pendiente es -100, o sea, cuando hay un desplazamiento de un pie por adelante, hay una queda de 100 pies.
- Bajado 1000 pies, entonces, aplicando la proporción:
1 pie H -> -100 pies V
x pie H -> -1000 pies V
Aplicando la multiplicación cruzada:
El cambio en la distancia horizontal es de 10 pies.
Un problema similar es dado en brainly.com/question/24766917