Ask question

Ask question

All categories

4 years ago

5

2m + 4

1 answer:

Evgen [1.6K]4 years ago

4 0

16 for both of the answers because m is 6 and 2m would be 2 x 6

You might be interested in

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

3 years ago

Read 2 more answers

How do you do this? algebra II

Pavel [41]

$3^x=23\\
x=\log_323\approx2.85$

6 0

3 years ago

Find the inverse of the function y = x2 – 12

vivado [14]

Answer: $y=\sqrt{x+12}$

Step-by-step explanation:

I hope you mean y = x² - 12 and not y = 2x - 12.

You switch the y and x variables:

x = y² - 12

And solve for y:

x + 12 = y²

$y=\sqrt{x+12}$

7 0

3 years ago

Please help ASAP it's due in a minute

grigory [225]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A quadrilateral has no pairs of parallel sides.what two shapes could be it

Basile [38]

Answer:

All trapezoids are quadrilaterals.

Step-by-step explanation:

Incorrect. Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. A trapezoid can never be a parallelogram. The correct answer is that all trapezoids are quadrilaterals.

8 0

3 years ago

Read 2 more answers