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Scilla [17]
3 years ago
10

Please help me with this question asap

Mathematics
1 answer:
aalyn [17]3 years ago
5 0
Right 
vertical
supplementary

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The distance between the bottom of a boat in the water line is called a draft. A boat in the water rises 14 feet above the water
vodomira [7]

Answer:

84

Step-by-step explanation:

because you multiplication the number

8 0
2 years ago
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Marilyn's cell phone company charges $35 a month for phone service plus $0.50 for each text message. How many text messages does
iren2701 [21]

Answer:

34

Step-by-step explanation:

52-35 = 17

$17 divided by $0.50 = 34 texst messages

7 0
2 years ago
The equation 5m=36.25 models a constant rate situation. What is the value of 7m
Bond [772]

Answer:

7m = 50.75

Step-by-step explanation:

5m=36.25

We can solve this for m by dividing each side by 5

5/5m=36.25/5

m = 7.25

We want to find 7m

7(7.25) = 50.75

3 0
3 years ago
Fill in the table with whole numbers to make 34 in four different ways
Keith_Richards [23]
It would be:

Tens | Ones
  3    +   4
  2    +  14
  1    +  24
  0    +  34

Hope this helped! c:
7 0
3 years ago
Read 2 more answers
If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
6 0
3 years ago
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