Solution:
The table which is about kind of jeans and it's color is
Style Color
regular light blue
loose fit indigo
boot cut washed
slim fit black
slim fit blue
(a) A regular can be chosen out of five colors, A loose fit can also be chosen in five colors,Similarly a boot cut as well as slim fit can also be chosen out of five colors.
If you consider this as a relation , total number of relation that is total jeans = 1×5 + 1×5 +1×5+1×5= 20 Jeans = 10 Pairs of jeans(Possible)
(b) Total number of jeans , if i have one pair of jeans of each possible style and color = As there are 5 colors and 4 styles , the jeans are in pair = 5×4×2=40
Number of Black color jeans = 2× black color in 4 styles= 2×4=8
Probability of an event = ![\frac{\text{Total possible outcome}}{\text{Total favorable outcome}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BTotal%20possible%20outcome%7D%7D%7B%5Ctext%7BTotal%20favorable%20outcome%7D%7D)
Probability of choosing a pair of black jeans at random=![\frac{8}{40}=\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B40%7D%3D%5Cfrac%7B1%7D%7B5%7D)
Answer:
B. 36
Step-by-step explanation:
Factoring 3x^2 + 12x + 36
3x^2 + 12x + 36
= 3(x^2 + 4x + 12)
<em>This is the most it can factor.</em>
None of the others factor.
Answer:
The answer to your question is: -2
Step-by-step explanation:
Data
log₁₀(1/100) = ?
We need to find a number that when we elevate 10 to this number, we get 1/100.
As the result is a fraction, the number must be negative.
And as the result must be 100, we can look for a root of 100 that gives 10, that root is square root (2).
Step-by-step explanation:
A'B'/AB = 5.1/1.7 = 3
B'C'/BC = 7.2/2.4 = 3
A'C'/AC = 7.5/2.5 = 3
These ratios are equal to the scale factor. These ratios are the scale factor.
<span>The spoke of a wheel reaches from the center of the wheel to its rim implies that the spoke of the wheel is describes the radius to the wheel. The circumference of a circle is given by C = 2πr. i.e. 48 = 2 x 3.14r = 6.28r => r = 48 / 6.28 = 7.64 inches.Hope this helps. Let me know if you need additional help!</span><span />