Please help asap!!!!

Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x

egoroff_w [7]

Answer:

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

Determine the slope (m):

$y = 1 -2x$

Rearrange into slope-intercept form:

$y = -2x+1$

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of $\displaystyle\frac{1}{2}$ . Plug this into $y=mx+b$ :

$y=\displaystyle\frac{1}{2} x+b$

Determine the y-intercept (b):

$y=\displaystyle\frac{1}{2} x+b$

Plug in the given point (1,3) and solve for b:

$3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}$

Therefore, the y-intercept is $\displaystyle \frac{5}{2}$ . Plug this back into $y=\displaystyle\frac{1}{2} x+b$ :

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

I hope this helps!

8 0

3 years ago

What is the Radical of 125???????

Serhud [2]

The square root is an inverse mathematical operation of a square. The square root of 125 is the value that is obtained after taking the square root of 125. The simplified radical form of square root of 125 is 5 √5.

4 0

3 years ago

A $20, 000 brand new car depreciate its value every year following the pattern, $16,000, $12,800, $10,240. How much will the car

seropon [69]

Answer:

Step-by-step explanation:

Use the info given in the exponential equation to find the value of b, the rate of decay.

$v(t)=a(b)^t$ where v(t) is the value of the car after a certain number of years, t, have gone by, a is the initial value, and b is the rate of decay. We have everything we need but b:

a = 20000

v(t) = 16000 after t = 1 year:

$16000=20000(b)^1$ so

b = .8 Taken in context, this means that the car depreciates 20% each year. Now we can solve the problem being asked of us, which is to find the value of the car after t = 5 years:

$v(t)=20000(.8)^5$ which simplifies down a bit to