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Thepotemich [5.8K]
2 years ago
7

There are only red and blue marbles in a box. The probability of choosing a red marble in

Mathematics
1 answer:
Nat2105 [25]2 years ago
3 0

Answer:

total marbles in the box is 600

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HELP PLS!! Whitney conducted a survey of grocery store customers to determine the most popular brand of bread. Of the 72 people
katovenus [111]

Answer:

  • 72 total
  • Hence population sample is 72
7 0
3 years ago
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Jan is 2/3 of Karyn's age. Jan's age 8 years ago is 2/5 of Katyn's age 4 yeats from now. Jan is how many younger than Karyn?
Elden [556K]

Answer:

12 years younger.

Step-by-step explanation:

Let Jan's age be J and Karyn's age be K.

J= \frac{2}{3}  K

Jan's age 8 years ago is 2/5 of Karyn's age 4 yeaRs from now.

J-8 = \frac{2}{5} (K+4)

=> (\frac{2}{3} - \frac{2}{5} ) K = \frac{8}{5} + 8

=> 4K = 48 X 3

=> K= 36.

=> J= 24.

So Jan is 12 years younger.

8 0
3 years ago
35x68<br> What is the answer
timurjin [86]

Answer:

2,380

Step-by-step explanation:

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3 years ago
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A swimming pool can be filled by either or both of two pipes of different diameters. it takes the smaller pipe twice the time th
liraira [26]
X+y= 213
X=2y

2y+ y=213,y=71
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Pls help asap whats the local min value of the function below?
shutvik [7]

Answer:

<em>given function has 2 minimums</em> - \frac{9}{4}  and  \frac{9}{4}  

Step-by-step explanation:

<u><em>Step 1.</em></u> g'(x) = 4x³ - 10x

<u><em>Step 2.</em></u> Find find the critical points:

4x³ - 10x = 2x(2x² - 5) = 0

x_{1} = - \sqrt{\frac{5}{2} } , x_{2} = 0 , x_{3} = \sqrt{\frac{5}{2} }

<u><em>Step 3.</em></u> g'(x) > 0 :  - \sqrt{\frac{5}{2} } < x < 0  or  x > \sqrt{\frac{5}{2} }

g'(x) < 0 :   x < - \sqrt{\frac{5}{2} }   or   0 < x < \sqrt{\frac{5}{2} }

<u><em>Step 4.</em></u>

If x ∈ ( - ∞ , - \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = - \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( - \sqrt{\frac{5}{2} } , 0 ) , g(x) is increasing ;

If x = 0 , g(x) has maximum value ;

If x ∈ ( 0 , \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( \sqrt{\frac{5}{2} } , ∞ ) , g(x) is increasing .

⇒ at ( - \sqrt{\frac{5}{2} } , - \frac{9}{4} ) and at ( \sqrt{\frac{5}{2} } , \frac{9}{4} ) , g(x) reaches its minimum

8 0
3 years ago
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