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Virty [35]
3 years ago
6

Which equation is a point slope form equation for line AB? y−6=−2(x+2) y−2=−2(x+2) y−2=−2(x+6) y−2=2(x+2) A graph with a line ru

nning through point A, with coordinates (-2, 6), and point B, with coordinates (2, -2)
Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

y-6=-2(x+2)

Step-by-step explanation:

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The Bilbo Company plans to manufacture decals for children's lunchboxes. Each decal
Gwar [14]

Answer: 1 -2ax²+2x-ax

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a rectangle: length x width

Replacing with the values given:

A = (2x+1) (1-ax)

A = [2x(1)] + [2x(-ax)] +[ 1(1)]+ [1 (-ax)]

A = 2x- 2ax² +1- ax

A = 1 -2ax²+2x-ax

In conclusion, the correct option is 1 -2ax²+2x-ax

Feel free to ask for more if needed or if you did not understand something.  

4 0
3 years ago
If needed i will show the other answers
bonufazy [111]

Answer:

It will take 518 calorie smoothy that she had for breakfast in the morning.

4 0
3 years ago
Read 2 more answers
Please help me with these. These are so hard.<br><br>​
LuckyWell [14K]

\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0
3 years ago
How do I solve this
sdas [7]
\bf \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;-------------------------------\\\\&#10;\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad &#10;\begin{cases}&#10;x^2+2x-24\implies (x+6)(x-4)\\&#10;--------------\\&#10;x^2-36\implies x^2-6^2\\&#10;(x-6)(x+6)&#10;\end{cases}

\bf \cfrac{2x}{(x+6)(x-4)}-\cfrac{x}{(x-6)(x+6)}\impliedby &#10;\begin{array}{llll}&#10;\textit{thus our LCD is}\\&#10;(x-6)(x+6)(x-4)&#10;\end{array}&#10;\\\\\\&#10;\cfrac{[(x-6)2x]~-~[(x-4)x]}{(x-6)(x+6)(x-4)}\implies \cfrac{2x^2-12x-x^2+4x}{(x-6)(x+6)(x-4)}&#10;\\\\\\&#10;\cfrac{x^2-8x}{(x-6)(x+6)(x-4)}
3 0
3 years ago
Calculate x Give your answer correct to 1 d.p. Х 35° 15 cm<br> it is a trigonometry question.​
OlgaM077 [116]

Here we are finding x, given the angle and adjacent side. To find x we will use the function cos as cos = a/h.

So let's do cos(35°) = 15cm / x

cos(35°) = 0.8 (1 dp)

x = 15 cm / cos(35°)

x = 18.3 cm (1 dp)

6 0
2 years ago
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