Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
Answer:
14 bags
Step-by-step explanation:
Dimension of lawn : 230 feet by 180 feet
area of rectangle is given by length * width
Since lawn is rectangular area of lawn = 230 feet * 180 feet = 41,400 sq. feet
Given that one bag of fertilizer covers 3000 square feet of lawn.
Thus , to find no. of bags required to cover whole lawn will be
total area of lawn/area which one bag of fertilizer covers
no. of bags required to cover whole lawn = 41,400 sq. feet/3000 sq. feet
= 13.8 bags.
As no. of bags cannot be fractional , hence rounding bag to nearest unit place is 14 bags.
It would take you about 13.3 hours to read 20 pages
Answer:
subtracting 5 from both sides
Step-by-step explanation:
please mark brainliest lol :)
Answer:
POG
Step-by-step explanation:
poggers + poggers = POGCHAMP
