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3 years ago

Using distributive property what is the value of the expression for 2(-5 + 3)

Mathematics

1 answer:

Vladimir [108]3 years ago

8 0

Answer:

-4

Step-by-step explanation:

According to the rules of the distributive property, you have to multiply the term outside of the parentheses with the terms inside the parentheses first.

1. 2(-5)=-10

2. 2(3)=6

The terms that we have are now -10 and 6. Add them together to get the final answer.

-10+6=-4

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Draw an arrow pointing to the left on left side of the open circle

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3 years ago

What is 0.7b^3•0.4b^9

Dennis_Churaev [7]

It's an expression that can be simplified to read

( 0.7 x 0.4 ) ( b³ x b⁹ )

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3 years ago

Expand 2(q+3) please

Y_Kistochka [10]

Answer:

2q + 6

Step-by-step explanation:

<u>Expand the expression with the help of distributive property.</u>

2(q + 3)
=> (2 x q) + (2 x 3)
=> 2q + 6

Hence, the expanded expression is 2q + 6.

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2 years ago

Read 2 more answers

Evaluate: 955-105 x 4 +118

drek231 [11]

Answer: −420x+1073

Step-by-step explanation:

Let's simplify step-by-step.

955−105x(4)+118=955+−420x+118

Combine Like Terms:

=955+−420x+118=(−420x)+(955+118)=−420x+1073

Answer: =−420x+1073

6 0

3 years ago

Read 2 more answers

For one toss of a certain coin, the probability that the outcome is heads is 0.6. If this coin is tossed 5 times, which of the f

pishuonlain [190]

Answer:

The probability is 0.33696

Step-by-step explanation:

The probability that the outcome will be heads x times is calculated using the following equation:

$P(x) = nCx*p^{x} *(1-p)^{n-x}$

nCx is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

This apply for variables that follows a binomial distribution. In which we have n independent and identical events with two possibles results: success and fail with a probability p and 1-p respectively.

So, In this case, n is equal to 5, and p is equal to 0.6 because we are going to call success the event in which the outcome of the coin is head.

Then, the probability that the outcome will be heads at least 4 times is calculated as:

P = P(4) + P(5)

Where P(4) is:

$P(4) = 5C4*0.6^{4} *(1-0.6)^{5-4}$

P(4)=0.2592

And P(5) is:

$P(5) = 5C5*0.6^{5} *(1-0.6)^{5-5}$

P(4)=0.07776

Finally, the probability is:

P = 0.2592 + 0.07776

P = 0.33696

5 0

3 years ago