Hey there! I'm happy to help!
Let's have the adult tickets be a and the children tickets be c.
a=2c (twice as many adult tickets as child tickets)
5a+2c=700 (dollar value of each ticket)
Have a wonderful day! I hope that the helps! :D
I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
Answer:
A) 150°
Step-by-step explanation:
Hope I helped you
Answer:
5 - (N x 15)
81 x 15 = 1215
5-1215=-1210
-1210 should be the 81st term
Step-by-step explanation:
Answer:
This means the cost of the item to you is $57.75. You will pay $57.75 for a item with original price of $82.50 when discounted 30%. In this example, if you buy an item at $82.50 with 30% discount, you will pay 82.50 - 24.75 = 57.75 dollars.
