Answer:
The x-axis would be ssideways and the y-axis would be straight up
Step-by-step explanation:
Because the x-axis is a flat line on the graph and the y-axis is stands up on the graph
Good evening Brian,
For this problem, let's look at what we're given. So we have a pool with a length that is 13 m (meters) longer than its width, and we're given the perimeter, or distance around the entire pool, which is 74 m.
We know that the pool has a rectangular shape and that the perimeter of a rectangle is <span>width + length + width + length ⇒ 2(W) + 2(L)</span>.
Given the information provided, we can rewrite the equation to fit this problem. Since we're told that the length is equal to 13 m + the width, so we can represent the length as W +13 m. We can now rewrite the perimeter equation to be:
2(w) + 2 (w + 13 m) ⇒ 2(w) + 2(w) + 2(13 m) ⇒ 4(w) + 26 m = 74 m.
We're down to one variable now so this should be easy. Subtract 26 m from both sides,
4(w) = 48 m
Now divide each side by 4 in order to find the width.
w = 12 m
-Hope this helps!
Answer:
x^2 -2xy -10y^2
x^2 -9xy +4 y^2
3x^3 +6x^2 -24 x +27
Step-by-step explanation:
3x^2-5xy -6y^2 -( 2x^2 -3xy+4y^2)
= 3x^2- 2x^2 -5xy +3xy-6y^2 -4 Y^2
= x^2 -2xy -10y^2
2x^2−5xy+y^2 -( x^2+4xy−3y^2)
=2 x^2 -x^2 -5xy -4xy +y^2 +3 y^2
=x^2 -9xy +4 y^2
7x^3−16x+18- (4x^3−6x^2+8x−9)
= 7x^3 -4x^3 + 6x^2-16x- 8x +18 +9
=3x^3 +6x^2 -24 x +27
That which is equivalent to tanθ is A sinθ/cosθ
To answer the question, we need to know what tanθ is
<h3>What is tanθ?</h3>
Tanθ is a trigonometric identity which is the tangent of the angle .
Now, from the unit circle, with radius, r = 1, we have that tanθ = y/x.
Also, the sine of the angle θ is sinθ = x/1 = x
And also, the cosine of the angle θ is cosθ = y/1 = y
Since we have that
- tanθ = y/x,
- sinθ = x and
- cosθ = y
Substituting the values of the variables y and x into tanθ, we have
tanθ = y/x
tanθ = sinθ/cosθ
So, that which is equivalent to tanθ is A sinθ/cosθ
Learn more about tanθ here:
brainly.com/question/26609988
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