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sattari [20]
3 years ago
11

Easy 25 points answer soon please

Mathematics
1 answer:
mario62 [17]3 years ago
6 0

Answer:

10

Step-by-step explanation:

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In the figure below, CD bisects m∠ACB, AB=BC, m∠BEC=90°, and m∠DCE=42°. Find the measure of ∠A.
vesna_86 [32]

Answer:  ∠A= 24\textdegree

Step-by-step explanation:

Since we have given that

CD bisects m∠ACB,

⇒  m∠ACD= m∠DCB =x (say)

And, AB=BC, m∠BEC=90°, and m∠DCE=42°

So,

m∠CAD=m∠ACD

In ΔDCE,

\angle DCE+\angle CED+\angle CDE=180\textdegree\\\\(\text{Sum of anlges in triangle is }180\textdegree)\\\\42\textdegree+90\textdegree+\angle CDE=180\textdegree\\\\132\textdegree+\angle CDE=180\textdegree\\\\\angle CDE=180\textdegree-132\textdegree\\\\+\angle CDE=48\textdegree

Now, in  ΔACD,

x+x=48\textdegree\\\\2x=48\textdegree\\\\\text{( Sum of interior anlges is equal to exterior angles )}\\\\x=\frac{48}{2}\\\\x=24\textdegree

Hence , ∠A= 24\textdegree

8 0
3 years ago
Read 2 more answers
Can someone help me complete this
Anon25 [30]
I can explain first you have to figure out how much money he makes in each hour so for example if I had 2 hours and 20 dollars evenly each hour would probably be 10 dollars :) hope it helped
8 0
3 years ago
Find the area of the shape shown below.
miskamm [114]

Answer:

28 units^2

Step-by-step explanation:

1. First, let's divide this figure into two shapes: a square and a trapezoid. (Look at the image below explanation for division).

2. Next, we should know the area formulas of the square and trapezoid.

  • Square: s^2, where s = side
  • \frac{a+b}{2}h, where a and b = top and bottom and h = height

3. Solving Area of Square and Trapezoid

  • 4^2 = 4 * 4 = 16. Area of square is 16
  • \frac{4+2}{2}*4 = \frac{6}{2} * 4 = 3 * 4 = 12. Area of trapezoid is 12.
  • 16 + 12 = 28

Therefore, the area of the figure is 28 units^2.

5 0
2 years ago
What does square mile mean
cestrela7 [59]
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6 0
3 years ago
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A number was written on the board. one student increased the number by 23, but another student decreased the number by 1. the fi
Softa [21]
Let the number be x.

First student increased the number by 23, therefore
⇒ x + 23

Second student decreased the number by 1, therefore
⇒ x - 1

The first student's result was 7 times greater than the result of the second student's, therefore
⇒ x + 23 = 7(x - 1)

----------------------------------------------
Solve for x:
----------------------------------------------
x + 23 = 7( x- 1)
x + 23 = 7x - 7
6x = 30
x = 5

--------------------------------------------------------------------------------------------
Answer: The  number on the board is 5.
--------------------------------------------------------------------------------------------
4 0
3 years ago
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