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3 years ago

HURRY PLZ! also please find tan as well!!! will mark brainliest!!

Mathematics

1 answer:

vazorg [7]3 years ago

3 0

I honestly don’t know man but don’t worry, if you get a bad score it won’t matter in 30 years :)

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Find the value of m. (-3/4)-⁴×(-3/4)-¹¹ = (-3/4)^m

tatiyna

Answer:

m = - 15

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , then

$(-\frac{3}{4}) ^{-4}$ × $(-\frac{3}{4}) ^{-11}$ = $(-\frac{3}{4}) ^{m}$ , that is

$(-\frac{3}{4}) ^{(-4-11)}$ = $(-\frac{3}{4}) ^{m}$

$(-\frac{3}{4}) ^{-15}$ = $(-\frac{3}{4}) ^{m}$

Equating exponents gives

m = - 15

4 0

3 years ago

4,750meters to kilmeters

Stella [2.4K]

4.75 Kilometers, you just divide by 1000

7 0

3 years ago

A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre

Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is tested if the consumption is not different, that is, if the subtraction of the means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if the consumption is different, that is, if the subtraction of the means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

Two groups of 22 patients, hence, the standard errors are:

$s_1 = \frac{45.1}{\sqrt{22}} = 9.6154$

$s_2 = \frac{26.4}{\sqrt{22}} = 5.6285$

The distribution of the differences is has:

$\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{25 - 0}{11.14}$

$t = 2.2438$

The p-value of the test is found using a two-tailed test, as we are testing if the mean is different of a value, with t = 2.2438 and 22 + 22 - 2 = 42 df.

Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

4 0

3 years ago

Hey will give brainliest

NeTakaya

Answer:

Step-by-step explanation:

i just had this problem

3 0

3 years ago

8-3x2 help with homework

Flura [38]

8-3x2

= 8 - (3x2)

= 8-6

= 2

7 0

3 years ago

Read 2 more answers