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3 years ago

In an arithmetic sequence Sn=n^2SN=N^2-2N .USE formula (Tn=Sn-Sn-1) to determine the value of Tn

Mathematics

1 answer:

gladu [14]3 years ago

7 0

Answer:

$T_n = 2n -3$

Step-by-step explanation:

Given

$S_n = n^2- 2n$

$T_n = S_n - S_{n-1$

Required

Find $T_n$

$S_n = n^2- 2n$

Calculate $S_{n-1$

$S_{n-1} = (n-1)^2- 2(n-1)$

$S_{n-1} = n^2-2n+1- 2n+2$

$S_{n-1} = n^2-2n- 2n+1+2$

$S_{n-1} = n^2-4n+3$

$T_n = S_n - S_{n-1$ becomes

$T_n = n^2 - 2n - (n^2 - 4n +3)$

$T_n = n^2 - 2n - n^2 + 4n -3$

$T_n = n^2 - n^2- 2n + 4n -3$

$T_n = 2n -3$

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kvasek [131]

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Your answer is the second option

3 0

3 years ago

Vis inversely proportional to r, when r = 3, V= 10.

guapka [62]

Answer:

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Step-by-step explanation:

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just olya [345]

Answer:

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Step-by-step explanation:

Consider the provided expression.

$(6r-1)(-8r-3)$

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$-48r^2-18r+8r+3$

Add the like terms.

$-48r^2-10r+3$

Hence, the required product is $-48r^2-10r+3$

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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In an arithmetic sequence Sn=n^2SN=N^2-2N .USE formula (Tn=Sn-Sn-1) to determine the value of Tn​

In an arithmetic sequence Sn=n^2SN=N^2-2N .USE formula (Tn=Sn-Sn-1) to determine the value of Tn