A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t
Solve for t
Solve using quadratic formula
After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
Answer:
AB + BC = AC Segment Addition Postulate
(x + 10) + (x + 14) = 22 Substitution
2x + 24 = 22 Simplify (added like terms)
2x = -2 Subtraction Property of Equality
x = -1 Divison Property of Equality
Answer: x = -1
Step-by-step explanation:
please give brainliest
Answer:
Ms, Erickson added 6x^3 plus -3x^2 and these terms have different exponents.l
Step-by-step explanation:
Answer:
1/3
Step-by-step explanation:
5 over 15
divide both by 5 to simplify 1 over 3