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Jobisdone [24]
3 years ago
8

What is the product? (6 r minus 1)(negative 8 r minus 3)

Mathematics
2 answers:
just olya [345]3 years ago
3 0

Answer:

The required product is -48r^2-10r+3

Step-by-step explanation:

Consider the provided expression.

(6r-1)(-8r-3)

Open the parentheses.

6r\left(-8r\right)+6r\left(-3\right)+\left(-1\right)\left(-8r\right)+\left(-1\right)\left(-3\right)

-6\cdot \:8rr-6\cdot \:3r+1\cdot \:8r+1\cdot \:3

-48r^2-18r+8r+3

Add the like terms.

-48r^2-10r+3

Hence, the required product is -48r^2-10r+3

Marta_Voda [28]3 years ago
3 0

Answer:

-47r²-10r+3

Step-by-step explanation:

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<em>Bringing</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>x</em><em> </em><em>terms</em><em> </em><em>together</em><em> </em><em>and</em><em> </em><em>constants</em><em> </em><em>together</em><em>:</em>

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