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2 years ago

Pythagorean Theorem a² + b² = c² find the missing side of the triangle

Mathematics

1 answer:

Mars2501 [29]2 years ago

8 0

Answer: a=c^2﹣b^2=152﹣132≈ 7.48331

Step-by-step explanation: 7.48331

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BONUS: What is the standard form of the linear model for Matuba?<br> Matuba: 312.4 308.6

Elodia [21]

Answer:

Step-by-step explanation: The standard form for linear equations in two variables is Ax+By=C. For example, 2x+3y=5 is a linear equation in standard form. When an equation is given in this form, it's pretty easy to find both intercepts (x and y).

3 0

2 years ago

find a number such that when 3/4 of it is added to 3½the sum is the same as when 2/3 of it is subtracted from 6½. PLEASE HELP

galben [10]

Answer:

- 120

Step-by-step explanation:

call x is the number you want to find

(3/4 )x + 3 $\frac{1}{2}$ = (2/3)x - 6 $\frac{1}{2}$
(3/4)x + (7/2) = (2/3)x - (13/2)
(3/4)x - (2/3)x = - (13 /2) - (7/2)
(1/12)x = -10
x = -10 / (1/12) = -120

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2 years ago

Alex is drawing rectangles with different areas on a centimetre grid.He can draw 3 different rectangles with an area of 12cm2.Ho

stiks02 [169]

Answer:

2.75 or 2

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Melvin conducted a series of surveys asking political candidates about the number of constituents they mail literature to. Each

damaskus [11]

Answer:

361.09

Step-by-step explanation:

Explanation:

Calculate the standard error of the mean, SE, using this formula, where is the standard deviation and n is the sample size.

For this situation, the sample size is 65, and the standard error of the mean is 44.8. Substitute these values into the formula, and solve for .

So the standard deviation is approximately 361.09.

5 0

2 years ago

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5. Mis the midpoint of CD. C has coordinates (-1,-1) and

lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $A(-2, -3) = (x_1, y_1)$

$B(1, 2) = (x_2, y_2)$

Thus:

$M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})$

$M(\frac{-1}{2}, \frac{-1}{2})$

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let $C(-1, -1) = (x_2, y_2)$

$D(?, ?) = (x_1, y_1)$

$M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})$

Rewrite the equation to find the coordinates of D

$3 = \frac{x_1 - 1}{2}$ and $5 = \frac{y_1 - 1}{2}$

Solve for each:

$3 = \frac{x_1 - 1}{2}$

$3*2 = \frac{x_1 - 1}{2}*2$

$6 = x_1 - 1$

$6 + 1= x_1 - 1 + 1$

$7 = x_1$

$x_1 = 7$

$5 = \frac{y_1 - 1}{2}$

$5*2 = \frac{y_1 - 1}{2}*2$

$10 = y_1 - 1$

$10 + 1= y_1 - 1 + 1$

$11 = y_1$

$y_1 = 11$

Coordinates of D is (7, 11)

7 0

2 years ago

Pythagorean Theorem a² + b² = c² find the missing side of the triangle ​

Pythagorean Theorem a² + b² = c² find the missing side of the triangle