Answer: Crickets make 172 chirps/min at 80 degrees Fahrenheit
Step-by-step explanation:
Step 1
Using the point slope formulae for Linear functions , we have that
y - y1 = m(x - x1)
where x and y are two points representing the temperature and chirps /min respectively
And
m= slope
Step 2 : Finding the slope , m
where x1=60
y1=92
x2= 75
y2=152
m= (y2-y1)/ (x2-x1)
= (152- 92)/(75-60)
=60/15 =4
Bringing down the point/slope formula and imputing the known values to find our equation to show the relationship cricket make per minute and the temperature
y - y1 = m(x - x1)
y - 92= 4(x - 60)
y - 92 = 4x -240
y = 4x - 240 + 92
y = 4x - 148
Step 3
To find the number of chirps be per minute (y) if the temperature is 80 degrees Fahrenheit( x)
y = 4(80) - 160
y = 320 - 148
y = 172 chirps/min at 80 degrees Fahrenheit
I don't either it is quite hard to be fair
You will notice that 48°, x, and x lie upon a straight line. The sum of those angles must then be equal to 180°. Which means:
48+x+x=180
48+2x=180
2x=132
x=66°
Answer:
Order from Least to Greatest
-4/7 < -1/19 < 7/4
Showing Work
Rewriting as fractions or any negatives if necessary:
-1/19, 7/4, -4/7
The least common denominator (LCD) is: 532.
Rewriting as equivalent fractions with the LCD:
-28/532, 931/532, -304/532
Ordering these fractions by the numerator:
-304/532 < -28/532 < 931/532
Therefore, the order of your input is:
-4/7 < -1/19 < 7/4
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
