You can either convert -3 into a fraction, or convert -2/5 into a decimal so you can solve this.
If you decide to convert -3, into a fraction, it would be -3/1, and you'd have to multiply that by the reciprocal of -2/5.
So, you'd have -3/1(-5/2)=15/2, which can be simplified to 7 1/2.
If you decide to convert -2/5 into a decimal, you would get -0.4. You would then divide -3 by -0.4, which is equal to 7.5.
Both 7.5 and 7 1/2 are correct answers, and if you were to convert 7.5 into a fraction and 7 1/2 into a decimal, you would notice that they are the same number, but in different forms.
The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
im sorry i dont know but this is for a challenge
Step-by-step explanation:
Answer:
<u></u>
Explanation:
The text and the model are garbled.
This is the question amended:
<em />
<em>Hyun Woo is riding a ferris wheel. H(t) models his height (in m) above the ground, t seconds after the ride starts. Here, t is entered in radians.</em>
<em>H(t) = -10 cos(2π/150 t)+10</em>
<em />
<em>When does Hyun Woo first reach a height of 16 m?</em>
<em />
<h2>Solution</h2>
<em />
When <em>Hyun Woo reaches a height of 16 m</em> the <em>model </em>states:
- <em>16 = -10 cos(2π/150 t)+10</em>
<em />
Then you must find the lowest positive value of t that is a solution of the equation.
Solve the equation:
- <em>16 = -10 cos(2π/150 t)+10</em>
- t = 52.86s ≈ 53 s ← answer
In the equation y=mx+b, the variable m represents the slope of the line. Therefore, the equation -5x+2y=10 can be rearranged into 2y=5x+10. Isolate the y to get y=2.5x+5. The slope of the line is 2.5