We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90
Answer:
3 22/45
Step-by-step explanation:
Answer:
The answer is x = 20
Step-by-step explanation:
If you set both equations equal to each other and solve for x, you will get 20.
3x+32 = 5x-8 add 8 to both sides
3x+40 = 5x subtract 3x from both sides
40 = 2x divide by 2 on both sides
20 = x
X^2 +2x +10 = 0
D = 4 -40 = - 36
x_1,2 = (-2 +/- sqrt(-36))/2 = (-2 +/- 6i)/2 = 2(-1 +/- 3i)/2 = -1 +/- 3i
x_1,2 = -1 +/- 3i or more understandably
x_1 = -1 -3i and x_2 = -1 +3i
hope this will help you
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