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Alina [70]
3 years ago
6

H=7+44t-16^2

Mathematics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

t_1\approx2.18

t_2\approx0.57

Step-by-step explanation:

h=7+44t-16t^2

27=7+44t-16t^2

0=-20+44t-16t^2

0=-16t^2+44t-20

t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

t=\frac{-44\pm\sqrt{44^2-4(-16)(-20)}}{2(-16)}

t=\frac{-44\pm\sqrt{1936-1280}}{-32}

t=\frac{-44\pm\sqrt{656}}{-32}

t=\frac{-44\pm4\sqrt{41}}{-32}

t=\frac{11}{8}\pm\frac{\sqrt{41}}{8}

t_1\approx2.18

t_2\approx0.57

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b) What percentage of the dam was released during the flood?

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Step-by-step explanation:

a) How much water was released during the flood?

The first step would be to find out how many seconds are in a week

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b) What percentage of the dam was released during the flood?

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