Answer:
The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i
Step-by-step explanation:
1) This claim is mistaken.
2) The Fundamental Theorem of Algebra assures that any polynomial f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

For example:
3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

We'll have <em>n </em>different complex roots, not necessarily 2i.
For example:
Taking 3 polynomial equations with real coefficients, with


2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

Answer:
The functions given are:
f(x) = x²
g(x) = f(-4x-3) + 1
First, find f(-4x-3):
f(x) = x²
f(-4x-3) = (-4x-3)²
Find g(x):
g(x) = f(-4x-3) + 1
g(x) = (-4x-3)² + 1
g(x) = (-1)² (4x+3)² + 1
g(x) = (4x+3)² + 1
First take
y = (x)²
Compress the graph along x axis by multiplying x with 4
y = (4x)²
Shift the graph left by 0.75 units, by adding 3 to x term.
y = (4x+3)²
Shift the graph up by 1 unit by adding 1 to the total terms.
y = (4x+3)² +1
Answer:
hiii the answer is A
Step-by-step explanation:
i used this formula -> 2πrh+2πr^2
Answer:
Fifteen is a factor of the number because both 3 and 5 are prime factors.
Step-by-step explanation:
2^3 * 3^2 * 5
= 2 * 2 * 2 * 3 * 3 * 5
As you can see from, the prime factors are 2, 3, and 5.
3 × 5 = 15, option A is correct.
Answer:
1.5
Step-by-step explanation:
You take 3% of 50.