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saveliy_v [14]
3 years ago
13

I need help with this question ​

Mathematics
1 answer:
Mrrafil [7]3 years ago
7 0
3x-14=4x-36
x=22
okeyyy
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A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m
____ [38]

Answer:

The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

\Delta < 0\\b^{2}-4*a*c

We'll have <em>n </em>different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

\Delta < 0

-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\

4 0
3 years ago
Describe how to transform the graph of f(x) = x² to obtain
lord [1]

Answer:

The functions given are:

f(x) = x²

g(x) = f(-4x-3) + 1

First, find f(-4x-3):

f(x) = x²

f(-4x-3) = (-4x-3)²

Find g(x):

g(x) = f(-4x-3) + 1

g(x) = (-4x-3)² + 1

g(x) = (-1)² (4x+3)² + 1

g(x) = (4x+3)² + 1

First take

y = (x)²

Compress the graph along x axis by multiplying x with 4

y = (4x)²

Shift the graph left by 0.75 units, by adding 3 to x term.

y = (4x+3)²

Shift the graph up by 1 unit by adding 1 to the total terms.

y = (4x+3)² +1

4 0
4 years ago
Help what is the surface area of each shape?
zavuch27 [327]

Answer:

hiii the answer is A

Step-by-step explanation:

i used this formula -> 2πrh+2πr^2

6 0
3 years ago
the prime factorization of a number is 2 to the power of 3 x 3 to the power of 2 x5 wich statement is true about these factors?
Naddik [55]

Answer:

Fifteen is a factor of the number because both 3 and 5 are prime factors.

Step-by-step explanation:

2^3 * 3^2 * 5

= 2 * 2 * 2 * 3 * 3 * 5

As you can see from, the prime factors are 2, 3, and 5.

3 × 5 = 15, option A is correct.

7 0
3 years ago
Read 2 more answers
Please help me preety please
Salsk061 [2.6K]

Answer:

1.5

Step-by-step explanation:

You take 3% of 50.

7 0
3 years ago
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