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3 years ago

What is the slope of the line on the graph?

Mathematics

1 answer:

musickatia [10]3 years ago

8 0

6/1 or 6.If you need an expkanation,it's rise over run.Rise as in goes up 6 and run as in across which is 1.6 divided by 1 is 6.

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Me ayudan xfaaaaaa (':

IceJOKER [234]

Answer:

$2(z + 8) 3 \\$

4 0

2 years ago

Question Help When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select a

S_A_V [24]

Answer:

Step-by-step explanation:

Here X no of defective batteries is binomial with p = 1% = 0.01

q = 1-p=0.99

(Because each battery is independent and there are only two outcomes)

Prob that shipment is accepted is for n =36, $P(X\leq 2)$

=P(x=0,1,2)

= $\Sigma^2_0 36Cr (0.01)^r (0.99)^{36-r}$

= 0.9944

8 0

3 years ago

Read 2 more answers

I aint gonna lie this is easy points hehehehe

Minchanka [31]

The answer is 8/125.....

4 0

2 years ago

Round 0.0825 to four decimal places

Sholpan [36]

Answer:

$0.0830$

Step-by-step explanation:

we know that

To Round a number

a) Decide which is the last digit to keep

b) Leave it the same if the next digit is less than $5$ (this is called rounding down)

c) But increase it by $1$ if the next digit is $5$ or more (this is called rounding up)

In this problem we have

$0.0825$

We want to keep the digit $2$

The next digit is $5$ which is greater or equal than $5$ , so increase the $2$ by 1 to $3$

therefore

the answer is

$0.0830$

8 0

2 years ago

Find Horizontal and Vertical Asymptotes for y=(1)/((x+2)^3)

Usimov [2.4K]

Answer:

Vertical asymptote: $x = -2$

Horizontal asymptote: $y = 0$ or x axis.

Step-by-step explanation:

The rational function is given as:

$y=\frac{1}{(x+2)^3}$

Vertical asymptotes are those values of $x$ for which the function is undefined or the graph moves towards infinity.

For a rational function, the vertical asymptotes can be determined by equating the denominator equal to zero and finding the values of $x$ .

Here, the denominator is $(x+2)^3$

Setting the denominator equal to zero, we get

$(x+2)^3=0\\(x+2)=0\\x=-2$

Therefore, the vertical asymptote occur at $x=-2$ .

Horizontal asymptotes are the horizontal lines when $x$ tends towards infinity.

For a rational function, if the degree of numerator is less than that of the denominator, then the horizontal asymptote is given as $y=0$ .

Here, there is no $x$ term in the numerator. So, degree is 0. The degree of the denominator is 3. So, the degree of numerator is less than that of denominator.

Therefore, the horizontal asymptote is at $y=0$ or x axis.

3 0

3 years ago