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Amiraneli [1.4K]
3 years ago
14

If the probability of a win is 0.2 and the probability of a draw is 0.64, what is the probability of a loss?

Mathematics
2 answers:
maw [93]3 years ago
8 0

Answer:

0.16 or 16%

Step-by-step explanation:

an easier way to work this out is to convert these decimals into percentage. to do this, multiply the number by 100:

0.2 x 100 = 20%

0.64 x 100 = 64%

a percentage is out of 100 (probability of a win = 20/100 = 1/5) so to work this out, you just have to subtract the percentages that are known from 100:

100% - 20% = 80%

80% - 64% = 16%

∴ the probability of a loss = 16% or 0.16 as a decimal.

<u>Another way to work this out</u> is to add together the amounts that are given then work out what number needs to be added to = 1

0.2 + 0.64 = 0.84

0.84 + <u>?</u> = 1

0.84 + <u>0.16</u> = 1

∴ the probability of a loss = 0.16

HOPE THIS WAS HELPFUL :-)

Veronika [31]3 years ago
5 0
To find the probability of a loss add .2 and .64 together. You will get .84. The remaining .16 is the probability of a loss. The probability of a loss is .16.
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Justin is saving money to buy a stereo. He has $25 saved in the bank right now. He earns $40 each week delivering newspapers.
mafiozo [28]

Answer:

y = 25 + 40x

Step-by-step explanation:

Let

y = the total amount of money Justin has

x = number of weeks

Amount Justin has in the bank = $25

Amount Justin earns per week = $40

Equation for how much money Justin has (including the amount he has in the bank) in x weeks

the total amount of money Justin has = Amount Justin has in the bank + (Amount Justin earns per week * number of weeks)

y = 25 + (40 * x)

y = 25 + 40x

The equation is

y = 25 + 40x

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3 years ago
What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?
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For this case we have the following function:
 f(x) =  tan(\frac{x^2}{9})
 The average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2- x1}
 Evaluating the function for the given interval we have:
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 f(1.25) = tan(\frac{1.25^2}{9})
 f(1.25) = 0.18
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 AVR = 0.4
 Answer:
 
the average value of on the closed interval [1.25, 2] is:
 
AVR = 0.4



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