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Amiraneli [1.4K]
3 years ago
14

If the probability of a win is 0.2 and the probability of a draw is 0.64, what is the probability of a loss?

Mathematics
2 answers:
maw [93]3 years ago
8 0

Answer:

0.16 or 16%

Step-by-step explanation:

an easier way to work this out is to convert these decimals into percentage. to do this, multiply the number by 100:

0.2 x 100 = 20%

0.64 x 100 = 64%

a percentage is out of 100 (probability of a win = 20/100 = 1/5) so to work this out, you just have to subtract the percentages that are known from 100:

100% - 20% = 80%

80% - 64% = 16%

∴ the probability of a loss = 16% or 0.16 as a decimal.

<u>Another way to work this out</u> is to add together the amounts that are given then work out what number needs to be added to = 1

0.2 + 0.64 = 0.84

0.84 + <u>?</u> = 1

0.84 + <u>0.16</u> = 1

∴ the probability of a loss = 0.16

HOPE THIS WAS HELPFUL :-)

Veronika [31]3 years ago
5 0
To find the probability of a loss add .2 and .64 together. You will get .84. The remaining .16 is the probability of a loss. The probability of a loss is .16.
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Answer:

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a) Yes. The counselor's claim is valid

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Step-by-step explanation:

Data given and notation  

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s=0.3 represent the sample standard deviation

n=36 sample size  

\mu_o =3.1 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

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p_v represent the p value for the test (variable of interest)  

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t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

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t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

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