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2 years ago

If the probability of a win is 0.2 and the probability of a draw is 0.64, what is the probability of a loss?

Mathematics

2 answers:

maw [93]2 years ago

8 0

Answer:

0.16 or 16%

Step-by-step explanation:

an easier way to work this out is to convert these decimals into percentage. to do this, multiply the number by 100:

0.2 x 100 = 20%

0.64 x 100 = 64%

a percentage is out of 100 (probability of a win = 20/100 = 1/5) so to work this out, you just have to subtract the percentages that are known from 100:

100% - 20% = 80%

80% - 64% = 16%

∴ the probability of a loss = 16% or 0.16 as a decimal.

<u>Another way to work this out</u> is to add together the amounts that are given then work out what number needs to be added to = 1

0.2 + 0.64 = 0.84

0.84 + <u>?</u> = 1

0.84 + <u>0.16</u> = 1

∴ the probability of a loss = 0.16

HOPE THIS WAS HELPFUL :-)

Veronika [31]2 years ago

5 0

To find the probability of a loss add .2 and .64 together. You will get .84. The remaining .16 is the probability of a loss. The probability of a loss is .16.

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Convert each of the following estimates of useful life to a straight-line depreciation rate, stated as a percentage: (a) 10 year

Rzqust [24]

Answer:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

Step-by-step explanation:

Under straight line method of depreciation, equal amount of the depreciation is reduced throughout the useful life of the asset. Using the following formula:

<u>Straight line depreciation rate = 1 / Useful Life x 100 </u>

So:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

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3 years ago

La familia Sánchez Olguín, quiere terminar de construir su casa y necesita S/.25000 para todos los gastos del acabado de la casa

erastova [34]

Extraemos los datos del problema:

Capital Inicial → C₀ = S/.25000
Interés bimestral → i = 8 % = 0.08
Periodos → n = 3

<h2 /><h2>Bimestre 1:</h2>

Capital Inicial Bimestre → C = S/.25000

Tasa de interés bimestral:

I = C×i

I = S/.25000 × 0.08

I = S/.2000

Monto final:

M = C + I

M = S/.25000 + S/.2000

M = S/.27000

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 27000 - 25000) / 25000

% = 8

<h2>Bimestre 2:</h2>

Capital Inicial Bimestre → C = S/.27000

Tasa de interés bimestral:

I = C×i

I = S/.27000 × 0.08

I = S/.2160

Monto final:

M = C + I

M = S/.27000 + S/.2160

M = S/.29160

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 29160 - 25000) / 25000

% = 16.64

<h2>Bimestre 3:</h2>

Capital Inicial Bimestre → C = S/.29160

Tasa de interés bimestral:

I = C×i

I = S/.29160 × 0.08

I = S/.2332.8

Monto final:

M = C + I

M = S/.29160 + S/.2332.8

M = S/ 31492.8

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 31492.8 - 25000) / 25000

% = 25.97

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Answer:

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Step-by-step explanation:

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Which equation described a line parallel to the line that connects points (-8 ,9) and (3, -4)?

musickatia [10]

Answer:

y = (-13/11)x - 5/11

Step-by-step explanation:

Where's the list of equations from which you're to choose?

The line that connects points (-8 ,9) and (3, -4) has the following slope:

9 - (-4)

m = ----------------- = -13/11

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Then the new line with this slope is y = (-13/11)x + c

and because (-8, 9) satisfies this equation, 9 = (-13/11)(-8) + c, and we need to calculate c from this. 9 = 104/11 + c, or

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Then the desired equation is y = (-13/11)x - 5/11

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