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Alla [95]
3 years ago
13

Which equation represents the graphed function?

Mathematics
2 answers:
NemiM [27]3 years ago
7 0
Y=1/4-2 is the correct answer. you go up one and over four. the y-intercept is -2
PtichkaEL [24]3 years ago
5 0

Answer:

y= 1/4x-2

Step-by-step explanation:

Let's use the two points we have to find the equation.

y = mx + b

-2 = m(0) + b

So b = -2

-1 = 4m - 2

4m = 1

m = 1/4

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Write an equation for the line through the points (7, 2) and (10,6) in point-slope form.
vovangra [49]

Answer:

Your answer is y-2=4/3(x-7)

Step-by-step explanation:

7 0
2 years ago
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Add<br><br> Show your work<br><br> -1.2 + (-1.7)
Kobotan [32]

Answer:

-2.9

Step-by-step explanation:

You are really subtracting. Note that if you have a positive & negative sign directly next to each other, you will subtract:

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2 years ago
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hat is the area of one base of the triangular prism? 24 square units 48 square units 160 square units 200 square units
Tems11 [23]

Answer:

24 a.)

Step-by-step explanation:

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3 0
2 years ago
Laura borrowed $1,990 at 5% for 2 years. what was the total interest?
Gnom [1K]

Answer:

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7 0
2 years ago
Which equation could generate the curve in the graph below?y=3x^2-2x+1
4vir4ik [10]
If you are asking what is the graph of y = 3x^2 -2x+1.

Then, the attached file would be the answer.

To check, b^2 - 4(a)(c), for each equation and use these facts:

If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.

If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.

If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots. 

7 0
3 years ago
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