A(an)_______is built-in preset calculation. formula function equation AutoSum

What are the values of the following expressions? In each line assume that,

MissTica

Answer:

double x = 2.5;

double y = -1.5;

int m = 18;

int n = 4;

string s = "Storm";

string t = "Watch";

The output of the expression "x + n*y - (x+n)*y" is "6.25".

and the output of expression "m/n + m%n" is "6".

Explanation:

for the first expression,

x + n*y - (x+n)*y ,put value of every variables in it.

=2.5+4*(-1.5)-(2.5+4)*(-1.5)

=2.5-6.0-(6.5*(-1.5)

=-3.5+9.75

=6.25

for the second expression,

m/n + m%n, put value of every variables in it.

=18/4 +18%4

=4+2 ("/ will give quotient and % will give remainder")

=6

4 0

4 years ago

which feature will configuring a SOHO network in which all ports on the public untrusted network will be forwarded to one workst

Ugo [173]

Answer:

Demilitarized zone (DMZ).

Explanation:

Demilitarized zone is a kind of security assurance scheme used by network administrator to detect network breach even before it gets to the secured network.

The private LAN is protected with a firewall and a DMZ is configured to allow access by untrusted users, on another workstation, which is a duplicate of the companies private local address.

7 0

3 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago

The text discusses three approaches to combining overall cost leadership and differentiation competitive advantages. Which of th

dedylja [7]

Answer:

C. deriving benefits from highly focused and high technology markets

Explanation:

Firms that engage in cost-leadership approach seek to combine a low per-unit income with large sales for profit making purposes. Typically, but not always, they are more inclined to market their products and services to a large population base or a niche with a high demand volume. While differentiation enables a company to accomplish a competitive advantage. A Competitive advantage enables a company to achieve more strides over other companies offering related product substitutes. It is an important marketing process that is of critical economic importance to a business.

It should be noted that deriving benefits from highly focused and high technology markets is not part of the approaches to combining overall cost leadership and differentiation competitive advantages.

3 0

3 years ago

How many iphones have Apple sold in 2019?

Phoenix [80]

Answer:

40.7 million iphones

Explanation:

Gupta. Apple's iPhone sales continued to decline in the third quarter of 2019. Apple sold 40.8 million iPhones, a year-over-year decline of 10.7%.

3 0

4 years ago

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A(an)_______is built-in preset calculation. formula function equation AutoSum​

A(an)_______is built-in preset calculation. formula function equation AutoSum