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3 years ago

Im confused on this question on how to solve it

Mathematics

1 answer:

Yakvenalex [24]3 years ago

7 0

Answer:

9/4

Step-by-step explanation:

see image

2/3 is 2 × 1/3.

We can separate the exponent into 1/3 power raised to the 2nd power. 1/3 power is the same as cube root.

27 and 8 are both perfect cubes. 3^3 and 2^3.

Thats how you go from 27/8 to 3/2.

Then square it.

see image.

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(6 – 4i) (6 + 4i)<br> simplify using imaginary numbers

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3 years ago

Need help asap!!!

antiseptic1488 [7]

Answer:

there is no solution

Step-by-step explanation:

y + 7 = 3x

6x - 2y = 6 which can be simplied to be 3x - y = 6 (divide by 2)

let y = 3x - 7

substitute: 3x -(3x - 7) = 6

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8 0

3 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

3 years ago

Im confused on this question on how to solve it​

Im confused on this question on how to solve it