The Query tool is the tool in MS access that will give user detailed report showing the most accurate and complete picture of employee attendance grouped by day
<h3>What is the
Query tool?</h3>
The Query tool helps to give answer to a simple question, perform calculations, combine data from a database
In conclusion, the Query tool is the tool in MS access that will give user detailed report showing the most accurate and complete picture of employee attendance grouped by day
Read more about Query tool
<em>brainly.com/question/5305223</em>
Answer:
int state[] = new int[8];
The technological tools that can be considered important for storing critical files are battery backup systems and drives. These devices can be used to store data and supply energy.
<h3>Battery backup systems</h3>
A home battery backup system is a device used to keep the electrical system working in the event when the electrical source goes down.
In computation, there are three major classes of batteries systems: Lead-Acid, Nickel-Cadmium, and Lithium-Ion.
An uninterruptible power supply (UPS) can be considered as a battery backup supply capable of charging when the power is on.
Learn more about battery backup systems here:
brainly.com/question/7125266
Answer:
A. Technicians A and B
Explanation:
When we're talking about generic scanners and about all OBD-II codes, in this case, both technician A and B is the correct answer. Because we can scan all OBD-II codes with a generic scan.
But the technician A just says generic tools must be able to read all generic OBD-II codes and technicians B just says generic scan tools must be able to read manufacture OBD-II code, both are correct.
Answer:
Explanation:
The following is written in Python. It takes in a file, it then reads all of the elements in the file and adds them to a list called myList. Then it sorts the list and uses the elements in that list to calculate the median. Once the median is calculated it returns it to the user. The code has been tested and the output can be seen in the image below.
def find_median(file):
file = open(file, 'r')
mylist = []
for number in file:
mylist.append(int(number))
numOfElements = len(mylist)
mylist.sort()
print(mylist)
if numOfElements % 2 == 0:
m1 = numOfElements / 2
m2 = (numOfElements / 2) + 1
m1 = int(m1) - 1
m2 = int(m2) - 1
median = (mylist[m1] + mylist[m2]) / 2
else:
m = (numOfElements + 1) / 2
m = int(m) - 1
median = mylist[m]
return median
print("Median: " + str(find_median('file1.txt')))
