Since Betty is applying for a software analyst role, she should specialize in INFORMATION TECHNOLOGY.
<span>Information technology or IT is defined as the study or use of systems in computers and telecommunications for storing, retrieving, and sending information.
</span>
Betty's role as a software analyst would be to:
1) <span> study the </span>software<span> application domain,
2) prepare </span>software<span> requirements and specification (</span>Software<span> Requirements Specification) documents.
3) be the link between the software users and software developers.</span>
Answer:
Oct 30, 2018 — ... design? A) difficulty level B) level duration C) perspective D) player-adjusted time. ... Add answer+5 pts. Log in to add comment. jonathanwilson is waiting for your help. Add your answer and earn points. ... New questions in Computer Science. answer ... classified the computer on the basic of operations.Explanation:
Answer:
See explaination
Explanation:
java code:
class DONALD
{
static class Node
{
int data;
Node next;
}
static Node head=null;
static int largestElement(Node head)
{
Int max=Integer.MIN_VALUE;
while(head!=null)
{
if(max<head.data)
max=head.data;
head=head.next;
}
return max;
}
static int smallestElement(Node head)
{
int min=Integer.MAX_VALUE;
while(head!=null)
{
if(min>head.data)
min=head.data;
head=head.next;
}
return min;
}
static void push(int data)
{
Node newNode=new Node();
newNode.data= data;
newNode.next=(head);
(head)=newNode;
}
static void printList(Node head)
{
while(head!=null)
{
System.out.println(head.data + " -> ");
head=head.next;
}
System.out.println("NULL");
}
public static void main(String[] args)
push(15);
push(14);
push(13);
push(22);
push(17);
System.out.println("Linked list is : ");
printList(head);
System.out.println("Maximum element in linked list: ");
System.out.println(largestelement(head));
System.out.print("Maximum element in Linked List: " );
System.out.print(smallestElement(head));
}
}
It has to be two people answering.Then vote braniest to who's answer you think is better.
Answer:
First: work out the difference (increase) between the two numbers you are comparing.
Increase = New Number - Original Number.
Then: divide the increase by the original number and multiply the answer by 100.
% increase = Increase ÷ Original Number × 100.
Explanation:
