All categories

3 years ago

How many ways can this be done?

Mathematics

2 answers:

Bas_tet [7]3 years ago

8 0

Answer:

Step-by-step explanation:

"Choose 3 appetizers out of 4" can be written in equation as: C(4,3), and that is 4!/[3!(4-3)!]=4 ways.

For main dishes, C(10,9)= 10!/9!(10-9)!=10 ways.

And for desserts, C(9,5)= 9!/[5!(9-5)!]=126 ways.

So ways in total are 4+10+126=140 ways to pick the meals.

RSB [31]3 years ago

5 0

This can be solved 6 ways depending on how many numbers u have

You might be interested in

dimaraw [331]

Answer:

$-7 < -4 < 0 < 7$

Step-by-step explanation:

Given

Change: -4, 7, -7 and 0

Required

Compare them

From the list of given options, we can observe that the inequality < is used in all options.

This implies that we arrange from least to highest

The least is -7

Then, -4

Then 0

And lastly, 7

So, we have:

$-7 < -4 < 0 < 7$

3 0

2 years ago

Which statement is true based on the diagram?

Margarita [4]

Answer:

option B

Step-by-step explanation:

Triangle RST~ TRIANGLE RQP

6 0

2 years ago

Read 2 more answers

Of the 25 sheep in a flock 34% are white. how many sheep are white

Iteru [2.4K]

8.5 sheep are white. 34% of 25 is 8.5.

7 0

3 years ago

Write the inequality for the linear inequality graphed below. You can

romanna [79]

Answer:

Step-by-step explanation:

5 0

2 years ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

3 years ago