Answer:
Following are the solution to this question:
Step-by-step explanation:
They provide various boxes or various objects. It also wants objects to be distributed into containers, so no container is empty. All we select k objects of r to keep no boxes empty, which (r C k) could be done. All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining
objects. All can be put in any of k boxes. Therefore, these
objects could in the
manner are organized. Consequently, both possible ways to do this are

Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one

Answer:
wats part A?
Step-by-step explanation:
Give me the data:)
Answer:
(x − 5) (x + 4)
Step-by-step explanation:
x² − x − 20
Factor using AC method:
1 × -20 = -20
Factors of -20 that add up to -1: -5 and 4
Divide by 1 and reduce: -5/1 and 4/1
(x − 5) (x + 4)
Answer:
5/24
Step-by-step explanation:
3/6 x 5/12 = 1/2 x 5/12 = 5/24