Step-by-step Answer:
There is a total of 10 coins, 5 dimes, 2 quarters and three pennies.
By picking a coin, it could be any that shows up out of the 10, so the probability of picking any coin in particular is 1 / 10.
If there are 5 dimes, the probability of picking ANY one particular dime is 1/10, so with 5, the probability of picking ANY of the five dimes is 5/10 = 1/2.
Going along the same line of thought, the probability of picking any of quarters and pennies would be 2/10+3/10 = 5/10 = 1/2 as well.
Answer:
Step-by-step explanation:
g(t)=|17-t|
A)g(11)=|17-11|
= |6|
= 6
B)g(12)=|17-12|
=|5|
=5
Answer:
1/5
Step-by-step explanation:
up 1, right 5
I think it would be (15-6)*5 because when it says 5 times you would cross out both B and D but then you have to find out what large as 15 minus 6 which i think would be (15-6) so your answer would be C. (15-6)*5
Just substitute the value of x from second equation into first equation:
N = x + y - n = 5
N = u + v + y - n = 5
N = 0 + y - n = 5
In short, N would be equal to y - n which is still equal to 5
Hope this helps!
