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3 years ago

I really need help with this dividend thing. Plz help ASAP

Mathematics

1 answer:

dimaraw [331]3 years ago

4 0

Answer:

45.26

Step-by-step explanation:

$36.50 \times 73 = (2664.5) \div 50 \\ = 53.29$

$53.29 \times 62 = (3303.98) \div 73 \\ = 45.26$

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|x+1| = 1/5x+1<br> .......................

Mademuasel [1]

Answer:

x=0, -5/3

Step-by-step explanation:

3 0

3 years ago

Last year, Lein earned $1,600 more than her husband. Together they earned $48,100. How much did each of them earn?

Illusion [34]

Lein earned $25,650
Her husband earned $22,450

5 0

3 years ago

A bag contains 1 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the prob

disa [49]

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Step-by-step explanation:

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3 years ago

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Select three ratios that are equivalent to 7:6

Otrada [13]

14:12

21:18

28:24

That should be the answer

6 0

3 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

3 years ago