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irinina [24]
3 years ago
15

I really need help with this dividend thing. Plz help ASAP

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

45.26

Step-by-step explanation:

36.50 \times 73 = (2664.5) \div 50  \\ = 53.29

53.29 \times 62 = (3303.98) \div 73 \\  = 45.26

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An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

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3 years ago
How do I write 3 2/3 in a from of a decimal?
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3.66666666 but u can round it to the third place 
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Which of the following functions has a domain of LaTeX: \left[2,7\right][ 2 , 7 ] and a range of LaTeX: \left[4,9\right][ 4 , 9
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3 years ago
In Mr. Smith's 7th Hour
tatiyna

binomial(16 + 7, 16) 2^(-(16 + 7)) = ((16 + 7)!)/(16! 7! 2^(16 + 7)) = 245157/8388608 ≈ 0.02922 ≈ 1/34.22

(assuming children are independent and male and female are equally likely)

| probability

less than 16 boys | 0.9534

16 or less boys | 0.9827

more than 16 boys | 0.01734

16 or more boys | 0.04657

fraction of boys | 16/(16 + 7) ≈ 0.695652

fraction of girls | 7/(16 + 7) ≈ 0.304348

expected value | 11.5

standard deviation | 2.398

variance | 5.75

11.5

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(a) The lake behind a dam has an area of 55 hectares. When the gates in the dam are open, water flows out at a rate of 75 000 li
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Answer:

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The cross-section is a right angled triangle BCD. BD = 10 cm, BC = 5.2 cm and ED = 18 cm.

(i) a) Work out the volume of the Prism.

b) Calculate the angle BEC

c) The point G lies on the line ED and GD = 7 cm. Work out angle BGE

(Cambridge Assessment International Education. 0580/42, October/November 2019, Q 4)

(a)

(b)(i)a

(b)(i)b

(b)(i)c

2. The diagram shows a sector of a circle of radius 3.8 cm.

The arc length is 7.7 cm.

(i) Calculate the value of y.

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(i)

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3

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