Answer:
it's 42 my bad...
Step-by-step explanation:
Answer:
Volume of right cylinder= 150.72 cu cm
Volume of cone= 314.159 cu cm
Volume of pyramid with base area 16= 160 cu cm
Volume of pyramid with length 3 =48 cu cm
Step-by-step explanation:
Volume of right cylinder = πr²h= 22/7 (4)²3= 150.72 cu cm
Volume of a cone = 1/3 πr²h= 1/3 (22/7) (5)²(12)= 314.159 cu cm
Volume of a pyramid = 1/3 ah= 1/3(16) (30)= 160 cu cm (where a= area and h= height)
Volume of pyramid= 1/3 (3*3)(16)= 48 cu cm
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
360 cm
Step-by-step explanation:
volume= length x width x height
8*5*9=360 cm
=3(3z)2-3
=3(9z2)-3
=27z^2-3
=3(9z^2-1)
=3(3z+1)(3z-1)
