How to find the derivative of this?

Mathematics

1 answer:

dimulka [17.4K]3 years ago

4 0

I cant see all the question but this is how you find the derivative of your function using the product rule.

Here you use the extension of the product rule to 3 factors which we'll write as:-

f(x), g(x) and h(x):-

Derivative = f'(x) g(x) h(x) + f(x) g'(x) h(x) + f(x) g(x) h'(x)

(3x - 1)(x + 4)(2x - 1)

derivative = 3(x + 4)(2x - 1) + (3x + 1)(1)(2x - 1) + (3x - 1)(x + 4)(2)

= 3(x + 4)(2x - 1) + (3x + 1)(2x - 1) + 2(3x - 1)(x + 4)

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2 years ago

The supplement of an angle is 50 less than 3 times its complement, find the measure of the angle

Lelechka [254]

Answer:

$20^{\circ}$ .

Step-by-step explanation:

Two angles are supplements of one another if their sum is $180^{\circ}$ .

Two angles are complements of one another if their sum is $90^{\circ}$ .

Let $x^{\circ}$ be the measure of the angle in question.

The supplement of this angle would be $(180 - x)^{\circ}$ .

The complement of this angle would be $(90 - x)^{\circ}$ .

According to the question:

$(180 - x) + 50 = 3\, (90 - x)$ .

Solve this equation for $x$ :

$x = 20$ .

Thus, this angle would measure should $20^{\circ}$ .

The supplement of this angle would measure $(180 - 20)^{\circ} = 160^{\circ}$ . The complement of this angle would measure $(90 - 20)^{\circ} = 70^{\circ}$ .

Three times the complement of this angle would be $3 \times 70^{\circ} = 210^{\circ}$ , which is indeed $50^{\circ}$ greater than the supplement of this angle.