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SOVA2 [1]
3 years ago
13

"complete the function table. use the given input (x) values and determine the corresponding output (y) values based on the give

n function. if no inputs or outputs are given --- provide your own."​

Mathematics
1 answer:
swat323 years ago
4 0

Answer:

-4, 6, 16, 26

Step-by-step explanation:

For each y-value, all you need to do is put x into the function or equation wherever there is an x, and the result will be the y-value.

When x = 0; y = 2(0)-4, or y = -4.

When x = 5; y = 2(5)-4 = 10-4 = 6

When x = 10; y = 2(10)-4 = 20-4 = 16

When x = 15; y = 2(15)-4 = 30-4 = 26

You might be interested in
Use the order of operations to evaluate this expression: 7 + (5 – 9)2 + 3(16 ÷ 8).
Jet001 [13]

Remember to use PEMDAS when solving.

=  7 + (5 – 9)2 + 3(16 ÷ 8)

= 7 + (-4)2 + 3(2)

= 7 + (-8) + 6

= -1 + 6

= 5

Best of Luck!

3 0
3 years ago
What is 12x34(234)+123x234
QveST [7]

Answer:

it's 124,254

Step-by-step explanation:

34 x 234 = 7,956

12 x 7956 = 95,472

123 x 234 = 28,782

95,472 + 28,782 = 124,254

hope that helps...

6 0
3 years ago
Read 2 more answers
Question : 10 = 7 - m
photoshop1234 [79]

Answer:

m = -3

Explanation:

3 0
3 years ago
Read 2 more answers
Need an answer for question 7 HURRY PLEASE 20 POINTS
Andrei [34K]

Answer:

2x^2 = 6x - 5.

-x^2 - 10x = 34.

These have only complex roots/

Step-by-step explanation:

3x^2 - 5x = -8

3x^2 - 5x + 8 = 0

There are complex roots if the discriminant  9b^2 - 4ac) is negative.

Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160

This is positive so the roots are real.

2x^2 = 6x - 5

2x^2 - 6x + 5 = 0

D = (-6)^2 - 4*2*5 =  36 - 40 = -4

So this has no real roots only complex ones.

12x = 9x^2 + 4

9x^2 - 12x + 4 = 0

D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.

- Real roots.

-x^2 - 10x = 34

x^2 + 10x + 34 = 0

D = (10)^2 - 4*1*34 = 100 - 136 = -36.

No real roots = only complex roots.

7 0
3 years ago
How to solve this algebraically?
Keith_Richards [23]
Ok so x+4-1 makes x-1 so i belive the answer could be 1/5 
7 0
3 years ago
Read 2 more answers
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