Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H
Now find the probability of flipping a head 4 times;

⁴
= (1/16)
Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16
Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16
(1/16)+(4/16)+(6/16)=11/16
Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.
Hope I helped :)
Idk if this is what you need but
Answer: $11.06
Step-by-step explanation: 3.7*2.99 = 11.063
Hopefully this helps, if its wrong lmk
<em>look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
7)
Read my note at the end of problem 5 in another post.
You already know this table represents an exponential function
since each y-coordinate is always the previous y-coordinate multiplied by 6.
That means b = 6, and you have
y = a(6)^x
Now we find "a". When x = 0, y = 5. That means a = 5.
The equation is
y = 5(6)^x