Consider the following two ordered bases of R2 R2: BC=={⟨1,2⟩,⟨3,5⟩},{⟨−1,1⟩,⟨1,−2⟩}. B={⟨1,2⟩,⟨3,5⟩},C={⟨−1,1⟩,⟨1,−2⟩}. Find th
Tamiku [17]
Answer:
This question is maybe r2+ =>()0?
Step-by-step explanation:
Answer:
x | 0 | 1 | 2 | 3
f(x) | - 7 | 0 | 5 | 8
Step-by-step explanation:
When you reflect a point say across the x-axis, the x-coordinate remains the same, but the y-coordinate is transformed into its opposite (its sign is changed). Therefore if the function f( x ) is reflected across the x - axis, it's new function would be y = - f( x ). This new function is function g, so you can also say y = - g( x ).
Given the following table ...
x | 0 | 1 | 2 | 3
f(x) | 7 | 0 | - 5 | - 8 ... we can keep the x - values constant, but take the opposite of each y - value, or " f( x ). " Doing so the new table should be the following -
x | 0 | 1 | 2 | 3
f(x) | - 7 | 0 | 5 | 8 ... note that 0 remains constant as you can't take it's opposite, it remains zero. Therefore, the function g is represented by the above table.
Answer:
2:48
Step-by-step explanation:
48 minutes passed and he went outside at 2:00 im not sure what they mean by write it in 2 ways though
You can write a subtraction problem as a division problem by subtracting one of the addends from the sum, then your other addend would be the answer.
Example :
5 + 6 = 11
11 - 5 = 6
See the attached diagram, it has all the information you need.
(a) If the green radii are all 1, then the orange diameters are all 2 + √2, so that the orange radii are (2 + √2)/2 = 1 + √2/2.
This is because we can join the radii of two adjacent green circles to form the sides of a square with side length equal to twice the radius - i.e. the diameter - of the green circles. The diagonal of any square occurs in a ratio to the side length of √2 to 1. Then we get the diameter of an orange circle by summing this diagonal length and two green radii, and hence the radius by dividing this by 2.
(b) We get the blue diameter in the same way. It has length (2 + √2) (1 + √2/2) = 3 + 2√2, so that the blue radius is (3 + 2√2)/2 = 3/2 + √2.
