All categories

2 years ago

A = p + prt solve for t

Mathematics

1 answer:

AveGali [126]2 years ago

7 0

Answer:

t = $\frac{A - p}{pr}$

Step-by-step explanation:

A = p + prt

A - p = p - p + prt

A - p = 0 + prt

A - p = prt

$\frac{A - p}{pr}$ = $\frac{prt}{pr}$

$\frac{A - P}{pr}$ = t

You might be interested in

Complete the ratio and find the answer

elena55 [62]

There are 12 inches in one foot. 120 x 12 = 1,440 inches. The correct ratio to be placed is the 5th one (aka 12 inches over 1 foot).

8 0

2 years ago

Find the area. plzz help

12345 [234]

The square has a side length of 9.

The area of the full square would be 9^2 = 9 x 9 = 81 square cm.

The area of the triangle is 1/2 x 4 x 3 = 6 square cm.

The area of the shape = 81 -6 = 75 square cm.

6 0

2 years ago

Which combination of integers can be used to generate the Pythagorean triple (5,12,13)

Kitty [74]

Answer:

x=3 and y=2

Step-by-step explanation:

The pythagorean triples are generated by two integrers x and y that can be found by solving the following system of equations:

$\left \{ {{x^{2}-y^{2}=5}\atop {2xy=12}} \atop {x^{2}+y^{2}=13}}\right.$

Solve the system of equations, and we get that the solution is x=3 and y=2.

Therefore, the combination of integrers that ca be used to generate the pythagorea triple are: x=3 and y=2

3 0

3 years ago

Read 2 more answers

HELP PLEASE Rory has 10 Gallons 8 cups of water to fill her aquarium how many cups of water does she have? Hint: 1 gallon = 16 c

Lesechka [4]

Answer:

Rory has 168 cups of water

Step-by-step explanation:

Since 1 Gallon is equals to 1 cups, multiply it by 10 gallons then add 8 cups to it

<u><em>Hope this helps</em></u>

4 0

2 years ago

Read 2 more answers

SOMEONE PLEASE PLEASE HELP PLEASE HELP

mr Goodwill [35]

Answer:

see explanation

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ = $\frac{1}{a^{-m} }$ , then

2 ÷ $10^{4}$ = 2 ÷ $\frac{1}{10^{-4} }$

To divide leave first, change ÷ to × , turn second upside down

= 2 × $10^{-4}$

6 0

2 years ago