All categories

3 years ago

If the sum of two expressions is 3x+5 and one expression is 5x-7 what is the other expression

Mathematics

1 answer:

ratelena [41]3 years ago

8 0

Answer:

-2x + 12

Step-by-step explanation:

If we call our other expression y, we can set up an equation tying together 3x + 5, y, and 5x - 7:

$(5x-7)+y=3x+5$

Solving for y by subtracting 5x - 7 from both sides will get us the expression we're looking for:

$y=3x+5-(5x-7)\\y=3x+5-5x+7\\y=-2x+12$

So the other expression in the sum is -2x + 12.

You might be interested in

Ravi buys lunch at a restaurant.

ipn [44]

The price of Ravi's lunch, before tax and tip was added to the total cost of the meal is $13.19.

<h3>What is the price of the lunch?</h3>

Both the tax and the tip paid would increase the cost of the meal. Thus, their dollar value has to be subtracted from the total amount he pays.

Value of the lunch after the tip has been removed = (1 - 0.2) x 17.92 = $14.34

Value of the lunch after the tax has been removed = (1 - 0.08) x $14.34 = $13.19

To learn more about taxes, please check: brainly.com/question/25311567

#SPJ1

5 0

2 years ago

In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm. Find the area of triangle ABC.

max2010maxim [7]

Answer:

Area = 42.43 square cm

Step-by-step explanation:

Using Heron's Formula :

$Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where \ s \ =\ \frac{a+ b+ c}{2}$

Find Area :

$s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15$

$Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}\\\\$

$= \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}$

$= 42 . 43 \ cm^2$

7 0

3 years ago

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$