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Dmitrij [34]
3 years ago
5

PLEASE HELP FAST

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

504 in3

Step-by-step explanation:

I did the I-Ready too.

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The minute of a hand clock is 4.2 inches long does the point of a hand move more or less than 24 inches in one hour
faltersainse [42]
C=2\pi r\\C=2\pi(4.2)\\C=8.2(3.14)\\C=25.748\\25.748>24

The minute hand moves more than 24 inches in one hour.
3 0
4 years ago
Please please help me
Lina20 [59]

Answer:

D

Step-by-step explanation:

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3 years ago
Solve for X. 3(x+2)=24
garik1379 [7]

ANSWER

My answer is in the photo above

7 0
3 years ago
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Won has a container with the shape below.
blagie [28]

Answer:

B. The shape can be broken into a rectangular prism and a rectangular pyramid.

C. The formula for the volume of this figure is V = B h + one-third B h.

D. The volume of the container is 2,760 centimeters cubed.

Step-by-step explanation:

I did the edge test.

3 0
3 years ago
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Solve the following equation; domain 0< x < 360; 3 cot x + sqrt 3 = 0
kondaur [170]
ANSWER

x =120 \degree \: or \: 300 \degree

EXPLANATION

We want to solve the trigonometric equation

3 \cot(x) + \sqrt{3} = 0

We group like terms to obtain,

3\cot(x) = - \sqrt{3}

Divide both sides of the equation by 3 to get,

\cot(x) = - \frac{ \sqrt{3} }{3}

We can reciprocate both sides to get,

\tan(x) = - \frac{3}{ \sqrt{3} }

We simplify the right hand side to get,

\tan(x) = - \sqrt{3}

Since the tangent ratio is negative, it implies that it is either in the second quadrant or fourth quadrant.

In the second quadrant,

x = 180 \degree - arctan( \sqrt{3})

x = 180 \degree - 60 \degree = 120 \degree

In the fourth quadrant,

x = 360 \degree - arctan( \sqrt{3})

x = 360 \degree - 60 \degree

x = 300 \degree
6 0
4 years ago
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