(2y-at)(y+2at)
Answer: <span><span><span>−<span><span>2<span>a^2</span></span><span>t^2</span></span></span>+<span><span><span>3a</span>t</span>y</span></span>+<span>2<span>y^<span>2
I hope this helps</span></span></span></span>
Answer:
Step-by-step explanation:
Ok
Answer:
m(
1000
123f
+
5
381p
)
Step-by-step explanation:
i dont know if thats right that my compution
sorry
It's not obvious here, but you're being asked to find a linear equation for the velocity of the car, given two points on the line that represents this velocity.
Find the slope of the line segment that connects the points (3 hr, 51 km/hr) and (5 hr, 59 km/hr). Graph this line. Where does this line intersect the y-axis? Find the y-value; it's your "y-intercept," b.
Now write the equation: velocity = (slope of line)*t + b
The units of measurement of "slope of line" must be "km per hour squared," and those of the "y-intercept" must be "km per hour."
Part B: Start with the y-intercept (calculated above). Plot it on the vertical axis of your graph. Now label the horizontal axis in hours: {0, 1, 2, 3, 4, 5, 6}. Draw a vertical line through t=6 hours. It will intercept both the horiz. axis and the sloping line representing the velocity as a function of time. Show only the part of the graph that extends from t=0 hours to t=6 hours.
